Base | Representation |
---|---|
bin | 110001011001000101… |
… | …001100110100101111 |
3 | 12001220001002121101101 |
4 | 301121011030310233 |
5 | 1332103220034043 |
6 | 40210305423531 |
7 | 3555143530531 |
oct | 613105146457 |
9 | 161801077341 |
10 | 53034143023 |
11 | 20545433674 |
12 | a34103aba7 |
13 | 5002549c24 |
14 | 27d16a3851 |
15 | 15a5e3024d |
hex | c5914cd2f |
53034143023 has 4 divisors (see below), whose sum is σ = 53044286688. Its totient is φ = 53023999360.
The previous prime is 53034142933. The next prime is 53034143059. The reversal of 53034143023 is 32034143035.
53034143023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53034143023 - 213 = 53034134831 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53034142982 and 53034143000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53037143023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5063986 + ... + 5074447.
It is an arithmetic number, because the mean of its divisors is an integer number (13261071672).
Almost surely, 253034143023 is an apocalyptic number.
53034143023 is a deficient number, since it is larger than the sum of its proper divisors (10143665).
53034143023 is a wasteful number, since it uses less digits than its factorization.
53034143023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10143664.
The product of its (nonzero) digits is 12960, while the sum is 28.
Adding to 53034143023 its reverse (32034143035), we get a palindrome (85068286058).
The spelling of 53034143023 in words is "fifty-three billion, thirty-four million, one hundred forty-three thousand, twenty-three".
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