Base | Representation |
---|---|
bin | 110001011001000101… |
… | …001100110011010101 |
3 | 12001220001002121021001 |
4 | 301121011030303111 |
5 | 1332103220033213 |
6 | 40210305423301 |
7 | 3555143530342 |
oct | 613105146325 |
9 | 161801077231 |
10 | 53034142933 |
11 | 205454335a2 |
12 | a34103ab31 |
13 | 5002549b85 |
14 | 27d16a37c9 |
15 | 15a5e301dd |
hex | c5914ccd5 |
53034142933 has 2 divisors, whose sum is σ = 53034142934. Its totient is φ = 53034142932.
The previous prime is 53034142927. The next prime is 53034143059. The reversal of 53034142933 is 33924143035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 27537079249 + 25497063684 = 165943^2 + 159678^2 .
It is a cyclic number.
It is not a de Polignac number, because 53034142933 - 217 = 53034011861 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53034142892 and 53034142901.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53034142333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26517071466 + 26517071467.
It is an arithmetic number, because the mean of its divisors is an integer number (26517071467).
Almost surely, 253034142933 is an apocalyptic number.
It is an amenable number.
53034142933 is a deficient number, since it is larger than the sum of its proper divisors (1).
53034142933 is an equidigital number, since it uses as much as digits as its factorization.
53034142933 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 116640, while the sum is 37.
Adding to 53034142933 its reverse (33924143035), we get a palindrome (86958285968).
The spelling of 53034142933 in words is "fifty-three billion, thirty-four million, one hundred forty-two thousand, nine hundred thirty-three".
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