Base | Representation |
---|---|
bin | 110001011001000101… |
… | …100100100011010011 |
3 | 12001220001021112200221 |
4 | 301121011210203103 |
5 | 1332103231141321 |
6 | 40210311453511 |
7 | 3555144414061 |
oct | 613105444323 |
9 | 161801245627 |
10 | 53034240211 |
11 | 2054549a697 |
12 | a341087297 |
13 | 5002582234 |
14 | 27d16cb031 |
15 | 15a5e4de41 |
hex | c591648d3 |
53034240211 has 4 divisors (see below), whose sum is σ = 53044549272. Its totient is φ = 53023931152.
The previous prime is 53034240209. The next prime is 53034240241. The reversal of 53034240211 is 11204243035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53034240211 - 21 = 53034240209 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53034240241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5146810 + ... + 5157103.
It is an arithmetic number, because the mean of its divisors is an integer number (13261137318).
Almost surely, 253034240211 is an apocalyptic number.
53034240211 is a deficient number, since it is larger than the sum of its proper divisors (10309061).
53034240211 is a wasteful number, since it uses less digits than its factorization.
53034240211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10309060.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 53034240211 its reverse (11204243035), we get a palindrome (64238483246).
The spelling of 53034240211 in words is "fifty-three billion, thirty-four million, two hundred forty thousand, two hundred eleven".
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