Base | Representation |
---|---|
bin | 100110100101100110010… |
… | …1101011110000111111001 |
3 | 200210000001202010020011112 |
4 | 1031023030231132013321 |
5 | 1143342403033141233 |
6 | 15140205344210105 |
7 | 1055105536120601 |
oct | 115131455360771 |
9 | 20700052106145 |
10 | 5303424115193 |
11 | 1765195720226 |
12 | 717a0a009935 |
13 | 2c6159410229 |
14 | 144989571c01 |
15 | 92e4a7ed048 |
hex | 4d2ccb5e1f9 |
5303424115193 has 2 divisors, whose sum is σ = 5303424115194. Its totient is φ = 5303424115192.
The previous prime is 5303424115097. The next prime is 5303424115207. The reversal of 5303424115193 is 3915114243035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5163242764729 + 140181350464 = 2272277^2 + 374408^2 .
It is a cyclic number.
It is not a de Polignac number, because 5303424115193 - 210 = 5303424114169 is a prime.
It is a super-2 number, since 2×53034241151932 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5303424115193.
It is not a weakly prime, because it can be changed into another prime (5303424112193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651712057596 + 2651712057597.
It is an arithmetic number, because the mean of its divisors is an integer number (2651712057597).
Almost surely, 25303424115193 is an apocalyptic number.
It is an amenable number.
5303424115193 is a deficient number, since it is larger than the sum of its proper divisors (1).
5303424115193 is an equidigital number, since it uses as much as digits as its factorization.
5303424115193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 194400, while the sum is 41.
The spelling of 5303424115193 in words is "five trillion, three hundred three billion, four hundred twenty-four million, one hundred fifteen thousand, one hundred ninety-three".
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