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5303441243332 = 222377569743159
BaseRepresentation
bin100110100101100110110…
…1110110011110011000100
3200210000002221100102120001
41031023031232303303010
51143342421424241312
615140211155251044
71055106134526061
oct115131556636304
920700087312501
105303441243332
1117651a4359911
12717a138a9a84
132c615cb2941b
1414498b94dc68
1592e4c083057
hex4d2cdbb3cc4

5303441243332 has 24 divisors (see below), whose sum is σ = 9684682761600. Its totient is φ = 2536392308736.

The previous prime is 5303441243299. The next prime is 5303441243381. The reversal of 5303441243332 is 2333421443035.

It is a junction number, because it is equal to n+sod(n) for n = 5303441243291 and 5303441243300.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6764769 + ... + 7507927.

It is an arithmetic number, because the mean of its divisors is an integer number (403528448400).

Almost surely, 25303441243332 is an apocalyptic number.

It is an amenable number.

5303441243332 is a deficient number, since it is larger than the sum of its proper divisors (4381241518268).

5303441243332 is a wasteful number, since it uses less digits than its factorization.

5303441243332 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 820755 (or 820753 counting only the distinct ones).

The product of its (nonzero) digits is 311040, while the sum is 37.

Adding to 5303441243332 its reverse (2333421443035), we get a palindrome (7636862686367).

The spelling of 5303441243332 in words is "five trillion, three hundred three billion, four hundred forty-one million, two hundred forty-three thousand, three hundred thirty-two".

Divisors: 1 2 4 23 46 92 77569 155138 310276 743159 1486318 1784087 2972636 3568174 7136348 17092657 34185314 68370628 57646100471 115292200942 230584401884 1325860310833 2651720621666 5303441243332