Base | Representation |
---|---|
bin | 111100010010110100100110… |
… | …1111000011001000100001001 |
3 | 2120112211012101200200210220222 |
4 | 1320211221031320121010021 |
5 | 1024003243313304214113 |
6 | 5115544320020555425 |
7 | 216465462215421134 |
oct | 17045511570310411 |
9 | 2515735350623828 |
10 | 530352458273033 |
11 | 143a9423a487080 |
12 | 4b595a39252b75 |
13 | 199c1039a81086 |
14 | 94d72a594721b |
15 | 414aa40462e08 |
hex | 1e25a4de19109 |
530352458273033 has 32 divisors (see below), whose sum is σ = 590641097840640. Its totient is φ = 472167591840000.
The previous prime is 530352458273003. The next prime is 530352458273041. The reversal of 530352458273033 is 330372854253035.
It is a cyclic number.
It is not a de Polignac number, because 530352458273033 - 210 = 530352458272009 is a prime.
It is not an unprimeable number, because it can be changed into a prime (530352458273003) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1813278758 + ... + 1813571216.
It is an arithmetic number, because the mean of its divisors is an integer number (18457534307520).
Almost surely, 2530352458273033 is an apocalyptic number.
It is an amenable number.
530352458273033 is a deficient number, since it is larger than the sum of its proper divisors (60288639567607).
530352458273033 is a wasteful number, since it uses less digits than its factorization.
530352458273033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 308069.
The product of its (nonzero) digits is 27216000, while the sum is 53.
The spelling of 530352458273033 in words is "five hundred thirty trillion, three hundred fifty-two billion, four hundred fifty-eight million, two hundred seventy-three thousand, thirty-three".
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