Base | Representation |
---|---|
bin | 110001011001001001… |
… | …110011100011000111 |
3 | 12001220010100221100012 |
4 | 301121021303203013 |
5 | 1332104022201330 |
6 | 40210351340435 |
7 | 3555160016201 |
oct | 613111634307 |
9 | 161803327305 |
10 | 53035350215 |
11 | 20546088651 |
12 | a34152171b |
13 | 5002880543 |
14 | 27d18d9771 |
15 | 15a60bcc95 |
hex | c592738c7 |
53035350215 has 4 divisors (see below), whose sum is σ = 63642420264. Its totient is φ = 42428280168.
The previous prime is 53035350167. The next prime is 53035350217. The reversal of 53035350215 is 51205353035.
53035350215 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53035350215 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53035350217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5303535017 + ... + 5303535026.
It is an arithmetic number, because the mean of its divisors is an integer number (15910605066).
Almost surely, 253035350215 is an apocalyptic number.
53035350215 is a deficient number, since it is larger than the sum of its proper divisors (10607070049).
53035350215 is a wasteful number, since it uses less digits than its factorization.
53035350215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10607070048.
The product of its (nonzero) digits is 33750, while the sum is 32.
The spelling of 53035350215 in words is "fifty-three billion, thirty-five million, three hundred fifty thousand, two hundred fifteen".
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