Base | Representation |
---|---|
bin | 100110100101101001101… |
… | …0100111111110100010001 |
3 | 200210000100111000212201121 |
4 | 1031023103110333310101 |
5 | 1143343114443440423 |
6 | 15140224352002241 |
7 | 1055111354611450 |
oct | 115132324776421 |
9 | 20700314025647 |
10 | 5303535140113 |
11 | 1765242361961 |
12 | 717a3b230381 |
13 | 2c6176413c52 |
14 | 14499a1d2b97 |
15 | 92e5542e45d |
hex | 4d2d353fd11 |
5303535140113 has 16 divisors (see below), whose sum is σ = 6384466293120. Its totient is φ = 4303745329536.
The previous prime is 5303535140107. The next prime is 5303535140149. The reversal of 5303535140113 is 3110415353035.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 5303535140113 - 221 = 5303533042961 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5303575140113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13155820 + ... + 13552957.
It is an arithmetic number, because the mean of its divisors is an integer number (399029143320).
Almost surely, 25303535140113 is an apocalyptic number.
It is an amenable number.
5303535140113 is a deficient number, since it is larger than the sum of its proper divisors (1080931153007).
5303535140113 is a wasteful number, since it uses less digits than its factorization.
5303535140113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26710296.
The product of its (nonzero) digits is 40500, while the sum is 34.
The spelling of 5303535140113 in words is "five trillion, three hundred three billion, five hundred thirty-five million, one hundred forty thousand, one hundred thirteen".
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