Base | Representation |
---|---|
bin | 1111011011110111000… |
… | …11111011000101101001 |
3 | 1212200221021121021101222 |
4 | 13231323203323011221 |
5 | 32142131110221131 |
6 | 1043350302351425 |
7 | 53213444360066 |
oct | 7557343730551 |
9 | 1780837537358 |
10 | 530353992041 |
11 | 194a16002a35 |
12 | 8695258b575 |
13 | 3b020966103 |
14 | 1b952697c6d |
15 | dbe088387b |
hex | 7b7b8fb169 |
530353992041 has 2 divisors, whose sum is σ = 530353992042. Its totient is φ = 530353992040.
The previous prime is 530353992023. The next prime is 530353992053. The reversal of 530353992041 is 140299353035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 526023825625 + 4330166416 = 725275^2 + 65804^2 .
It is a cyclic number.
It is not a de Polignac number, because 530353992041 - 238 = 255476085097 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 530353991983 and 530353992001.
It is not a weakly prime, because it can be changed into another prime (530353994041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265176996020 + 265176996021.
It is an arithmetic number, because the mean of its divisors is an integer number (265176996021).
Almost surely, 2530353992041 is an apocalyptic number.
It is an amenable number.
530353992041 is a deficient number, since it is larger than the sum of its proper divisors (1).
530353992041 is an equidigital number, since it uses as much as digits as its factorization.
530353992041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 437400, while the sum is 44.
The spelling of 530353992041 in words is "five hundred thirty billion, three hundred fifty-three million, nine hundred ninety-two thousand, forty-one".
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