Base | Representation |
---|---|
bin | 100110100101101001110… |
… | …1100001110110111111111 |
3 | 200210000100220111022222211 |
4 | 1031023103230032313333 |
5 | 1143343123023343403 |
6 | 15140225130321251 |
7 | 1055111460440443 |
oct | 115132354166777 |
9 | 20700326438884 |
10 | 5303541231103 |
11 | 1765245842135 |
12 | 717a41289227 |
13 | 2c617776749b |
14 | 14499ad3a823 |
15 | 92e55c3406d |
hex | 4d2d3b0edff |
5303541231103 has 4 divisors (see below), whose sum is σ = 5486421963240. Its totient is φ = 5120660498968.
The previous prime is 5303541231101. The next prime is 5303541231127. The reversal of 5303541231103 is 3011321453035.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5303541231103 - 21 = 5303541231101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5303541231101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91440366025 + ... + 91440366082.
It is an arithmetic number, because the mean of its divisors is an integer number (1371605490810).
Almost surely, 25303541231103 is an apocalyptic number.
5303541231103 is a deficient number, since it is larger than the sum of its proper divisors (182880732137).
5303541231103 is a wasteful number, since it uses less digits than its factorization.
5303541231103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 182880732136.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 5303541231103 its reverse (3011321453035), we get a palindrome (8314862684138).
The spelling of 5303541231103 in words is "five trillion, three hundred three billion, five hundred forty-one million, two hundred thirty-one thousand, one hundred three".
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