Base | Representation |
---|---|
bin | 100110100101101001110… |
… | …1100101101001011101011 |
3 | 200210000100220201122021121 |
4 | 1031023103230231023223 |
5 | 1143343123041331433 |
6 | 15140225133120111 |
7 | 1055111461465405 |
oct | 115132354551353 |
9 | 20700326648247 |
10 | 5303541355243 |
11 | 176524591742a |
12 | 717a41329037 |
13 | 2c61777abb41 |
14 | 14499ad6db75 |
15 | 92e55c5ac2d |
hex | 4d2d3b2d2eb |
5303541355243 has 2 divisors, whose sum is σ = 5303541355244. Its totient is φ = 5303541355242.
The previous prime is 5303541355213. The next prime is 5303541355247. The reversal of 5303541355243 is 3425531453035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5303541355243 - 233 = 5294951420651 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5303541355243.
It is not a weakly prime, because it can be changed into another prime (5303541355247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651770677621 + 2651770677622.
It is an arithmetic number, because the mean of its divisors is an integer number (2651770677622).
Almost surely, 25303541355243 is an apocalyptic number.
5303541355243 is a deficient number, since it is larger than the sum of its proper divisors (1).
5303541355243 is an equidigital number, since it uses as much as digits as its factorization.
5303541355243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620000, while the sum is 43.
The spelling of 5303541355243 in words is "five trillion, three hundred three billion, five hundred forty-one million, three hundred fifty-five thousand, two hundred forty-three".
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