53035542433 has 2 divisors, whose sum is σ = 53035542434. Its totient is φ = 53035542432.

The previous prime is 53035542407. The next prime is 53035542463. The reversal of 53035542433 is 33424553035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28018742544 + 25016799889 = 167388^2 + 158167^2 .

It is a cyclic number.

It is not a de Polignac number, because 53035542433 - 2¹³ = 53035534241 is a prime.

It is a super-2 number, since 2×53035542433² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53035542392 and 53035542401.

It is not a weakly prime, because it can be changed into another prime (53035542463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26517771216 + 26517771217.

It is an arithmetic number, because the mean of its divisors is an integer number (26517771217).

Almost surely, 2^53035542433 is an apocalyptic number.

It is an amenable number.

53035542433 is a deficient number, since it is larger than the sum of its proper divisors (1).

53035542433 is an equidigital number, since it uses as much as digits as its factorization.

53035542433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324000, while the sum is 37.

The spelling of 53035542433 in words is "fifty-three billion, thirty-five million, five hundred forty-two thousand, four hundred thirty-three".