Base | Representation |
---|---|
bin | 111100010010111111101011… |
… | …1010011110000110001111101 |
3 | 2120112220110202222212212122120 |
4 | 1320211333113103300301331 |
5 | 1024004141014110410013 |
6 | 5120003251435233153 |
7 | 216500263424306100 |
oct | 17045772723606175 |
9 | 2515813688785576 |
10 | 530376238763133 |
11 | 143aa33329a1284 |
12 | 4b59a5752a87b9 |
13 | 199c3359751aa9 |
14 | 94d84bdd62737 |
15 | 414b483044123 |
hex | 1e25fd74f0c7d |
530376238763133 has 96 divisors (see below), whose sum is σ = 850029915829248. Its totient is φ = 292995480960000.
The previous prime is 530376238763101. The next prime is 530376238763153. The reversal of 530376238763133 is 331367832673035.
It is not a de Polignac number, because 530376238763133 - 25 = 530376238763101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530376238763153) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 40795027633 + ... + 40795040633.
It is an arithmetic number, because the mean of its divisors is an integer number (8854478289888).
Almost surely, 2530376238763133 is an apocalyptic number.
It is an amenable number.
530376238763133 is a deficient number, since it is larger than the sum of its proper divisors (319653677066115).
530376238763133 is a wasteful number, since it uses less digits than its factorization.
530376238763133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21523 (or 21516 counting only the distinct ones).
The product of its (nonzero) digits is 102876480, while the sum is 60.
The spelling of 530376238763133 in words is "five hundred thirty trillion, three hundred seventy-six billion, two hundred thirty-eight million, seven hundred sixty-three thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •