Base | Representation |
---|---|
bin | 1111011011111100100… |
… | …11110111000111110101 |
3 | 1212201001111101110122212 |
4 | 13231332103313013311 |
5 | 32142224412110031 |
6 | 1043355031103205 |
7 | 53214544400663 |
oct | 7557623670765 |
9 | 1781044343585 |
10 | 530400113141 |
11 | 194a3a044448 |
12 | 86965b11b05 |
13 | 3b02a393ac2 |
14 | 1b958861c33 |
15 | dbe494412b |
hex | 7b7e4f71f5 |
530400113141 has 8 divisors (see below), whose sum is σ = 544744613280. Its totient is φ = 516056105808.
The previous prime is 530400113069. The next prime is 530400113167. The reversal of 530400113141 is 141311004035.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530400113141 - 210 = 530400112117 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530400173141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3410030 + ... + 3562176.
It is an arithmetic number, because the mean of its divisors is an integer number (68093076660).
Almost surely, 2530400113141 is an apocalyptic number.
It is an amenable number.
530400113141 is a deficient number, since it is larger than the sum of its proper divisors (14344500139).
530400113141 is a wasteful number, since it uses less digits than its factorization.
530400113141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 246403.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 530400113141 its reverse (141311004035), we get a palindrome (671711117176).
The spelling of 530400113141 in words is "five hundred thirty billion, four hundred million, one hundred thirteen thousand, one hundred forty-one".
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