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530400214103 = 895615922223
BaseRepresentation
bin1111011011111100101…
…00001111110001010111
31212201001111120121011012
413231332110033301113
532142224423322403
61043355033202435
753214545301224
oct7557624176127
91781044517135
10530400214103
11194a3a103291
1286965b6041b
133b02a3caa46
141b95888a94b
15dbe4963ed8
hex7b7e50fc57

530400214103 has 4 divisors (see below), whose sum is σ = 530406225888. Its totient is φ = 530394202320.

The previous prime is 530400214051. The next prime is 530400214187. The reversal of 530400214103 is 301412004035.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301412004035 = 560282400807.

It is a cyclic number.

It is not a de Polignac number, because 530400214103 - 224 = 530383436887 is a prime.

It is a super-3 number, since 3×5304002141033 (a number of 36 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530400213103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2871551 + ... + 3050672.

It is an arithmetic number, because the mean of its divisors is an integer number (132601556472).

Almost surely, 2530400214103 is an apocalyptic number.

530400214103 is a deficient number, since it is larger than the sum of its proper divisors (6011785).

530400214103 is an equidigital number, since it uses as much as digits as its factorization.

530400214103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6011784.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 530400214103 its reverse (301412004035), we get a palindrome (831812218138).

The spelling of 530400214103 in words is "five hundred thirty billion, four hundred million, two hundred fourteen thousand, one hundred three".

Divisors: 1 89561 5922223 530400214103