Base | Representation |
---|---|
bin | 1111011011111100101… |
… | …00001111110000100011 |
3 | 1212201001111120121002021 |
4 | 13231332110033300203 |
5 | 32142224423322201 |
6 | 1043355033202311 |
7 | 53214545301121 |
oct | 7557624176043 |
9 | 1781044517067 |
10 | 530400214051 |
11 | 194a3a103244 |
12 | 86965b60397 |
13 | 3b02a3caa06 |
14 | 1b95888a911 |
15 | dbe4963ea1 |
hex | 7b7e50fc23 |
530400214051 has 2 divisors, whose sum is σ = 530400214052. Its totient is φ = 530400214050.
The previous prime is 530400214027. The next prime is 530400214187. The reversal of 530400214051 is 150412004035.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530400214051 - 223 = 530391825443 is a prime.
It is not a weakly prime, because it can be changed into another prime (530400214021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265200107025 + 265200107026.
It is an arithmetic number, because the mean of its divisors is an integer number (265200107026).
Almost surely, 2530400214051 is an apocalyptic number.
530400214051 is a deficient number, since it is larger than the sum of its proper divisors (1).
530400214051 is an equidigital number, since it uses as much as digits as its factorization.
530400214051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 530400214051 its reverse (150412004035), we get a palindrome (680812218086).
The spelling of 530400214051 in words is "five hundred thirty billion, four hundred million, two hundred fourteen thousand, fifty-one".
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