530401132431 has 12 divisors (see below), whose sum is σ = 771208712560. Its totient is φ = 351259027200.

The previous prime is 530401132397. The next prime is 530401132433. The reversal of 530401132431 is 134231104035.

It is a happy number.

530401132431 is a `hidden beast` number, since 5 + 3 + 0 + 401 + 13 + 243 + 1 = 666.

It is not a de Polignac number, because 530401132431 - 2⁹ = 530401131919 is a prime.

It is a super-2 number, since 2×530401132431² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 530401132395 and 530401132404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530401132433) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 195142546 + ... + 195145263.

Almost surely, 2^530401132431 is an apocalyptic number.

530401132431 is a deficient number, since it is larger than the sum of its proper divisors (240807580129).

530401132431 is a wasteful number, since it uses less digits than its factorization.

530401132431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 390287966 (or 390287963 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 530401132431 its reverse (134231104035), we get a palindrome (664632236466).

The spelling of 530401132431 in words is "five hundred thirty billion, four hundred one million, one hundred thirty-two thousand, four hundred thirty-one".