Base | Representation |
---|---|
bin | 100110100101111000001… |
… | …1010001111101100110001 |
3 | 200210001121111010112100000 |
4 | 1031023300122033230301 |
5 | 1143400114400231103 |
6 | 15140345021420213 |
7 | 1055126431043334 |
oct | 115136032175461 |
9 | 20701544115300 |
10 | 5304023055153 |
11 | 1765472814729 |
12 | 717b5670a669 |
13 | 2c6223527484 |
14 | 144a04d2061b |
15 | 92e831abaa3 |
hex | 4d2f068fb31 |
5304023055153 has 48 divisors (see below), whose sum is σ = 8118230702400. Its totient is φ = 3459354485184.
The previous prime is 5304023055143. The next prime is 5304023055157. The reversal of 5304023055153 is 3515503204035.
5304023055153 is a `hidden beast` number, since 5 + 30 + 4 + 0 + 23 + 0 + 551 + 53 = 666.
It is not a de Polignac number, because 5304023055153 - 210 = 5304023054129 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5304023055157) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3904750 + ... + 5084792.
It is an arithmetic number, because the mean of its divisors is an integer number (169129806300).
Almost surely, 25304023055153 is an apocalyptic number.
5304023055153 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
It is an amenable number.
5304023055153 is a deficient number, since it is larger than the sum of its proper divisors (2814207647247).
5304023055153 is a wasteful number, since it uses less digits than its factorization.
5304023055153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1180460 (or 1180448 counting only the distinct ones).
The product of its (nonzero) digits is 135000, while the sum is 36.
Adding to 5304023055153 its reverse (3515503204035), we get a palindrome (8819526259188).
The spelling of 5304023055153 in words is "five trillion, three hundred four billion, twenty-three million, fifty-five thousand, one hundred fifty-three".
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