Base | Representation |
---|---|
bin | 11000000111101011001011… |
… | …00100011111101011000011 |
3 | 20221210121011120200210012202 |
4 | 30003311211210133223003 |
5 | 23423002420313012120 |
6 | 304450205025343415 |
7 | 14113013653314131 |
oct | 1403654544375303 |
9 | 227717146623182 |
10 | 53040255204035 |
11 | 1599a278340430 |
12 | 5b47682197b6b |
13 | 23798a014a728 |
14 | d1523a940751 |
15 | 61ea7349b875 |
hex | 303d6591fac3 |
53040255204035 has 32 divisors (see below), whose sum is σ = 70023757547520. Its totient is φ = 38248752960000.
The previous prime is 53040255204019. The next prime is 53040255204043.
53040255204035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53040255204035 - 24 = 53040255204019 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53040255204035.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5536070 + ... + 11693099.
It is an arithmetic number, because the mean of its divisors is an integer number (2188242423360).
Almost surely, 253040255204035 is an apocalyptic number.
53040255204035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53040255204035 is a deficient number, since it is larger than the sum of its proper divisors (16983502343485).
53040255204035 is a wasteful number, since it uses less digits than its factorization.
53040255204035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17229659.
The product of its (nonzero) digits is 360000, while the sum is 38.
The spelling of 53040255204035 in words is "fifty-three trillion, forty billion, two hundred fifty-five million, two hundred four thousand, thirty-five".
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