Base | Representation |
---|---|
bin | 110001011001011100… |
… | …110011011000000011 |
3 | 12001220110201221122200 |
4 | 301121130303120003 |
5 | 1332111311031433 |
6 | 40211050204243 |
7 | 3555250240215 |
oct | 613134633003 |
9 | 161813657580 |
10 | 53040330243 |
11 | 2054897a17a |
12 | a343123683 |
13 | 50039051c4 |
14 | 27d24345b5 |
15 | 15a6753613 |
hex | c59733603 |
53040330243 has 24 divisors (see below), whose sum is σ = 78731024736. Its totient is φ = 34384176000.
The previous prime is 53040330241. The next prime is 53040330311. The reversal of 53040330243 is 34203304035.
It is a happy number.
53040330243 is a `hidden beast` number, since 5 + 304 + 0 + 330 + 24 + 3 = 666.
It is not a de Polignac number, because 53040330243 - 21 = 53040330241 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53040330241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 526818 + ... + 619368.
It is an arithmetic number, because the mean of its divisors is an integer number (3280459364).
Almost surely, 253040330243 is an apocalyptic number.
53040330243 is a deficient number, since it is larger than the sum of its proper divisors (25690694493).
53040330243 is a wasteful number, since it uses less digits than its factorization.
53040330243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 94315 (or 94312 counting only the distinct ones).
The product of its (nonzero) digits is 12960, while the sum is 27.
Adding to 53040330243 its reverse (34203304035), we get a palindrome (87243634278).
The spelling of 53040330243 in words is "fifty-three billion, forty million, three hundred thirty thousand, two hundred forty-three".
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