Base | Representation |
---|---|
bin | 100110100101111101110… |
… | …0101000110011001001111 |
3 | 200210002002112202011201212 |
4 | 1031023323211012121033 |
5 | 1143401010333344444 |
6 | 15140415354125035 |
7 | 1055134164631106 |
oct | 115137345063117 |
9 | 20702075664655 |
10 | 5304210449999 |
11 | 17655595781aa |
12 | 717ba942077b |
13 | 2c62532ba1b6 |
14 | 144a21b8103d |
15 | 92e9487619e |
hex | 4d2fb94664f |
5304210449999 has 4 divisors (see below), whose sum is σ = 5304879590064. Its totient is φ = 5303541309936.
The previous prime is 5304210449981. The next prime is 5304210450001. The reversal of 5304210449999 is 9999440124035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5304210449999 - 228 = 5303942014543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5304210439999) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 334558142 + ... + 334573995.
It is an arithmetic number, because the mean of its divisors is an integer number (1326219897516).
Almost surely, 25304210449999 is an apocalyptic number.
5304210449999 is a deficient number, since it is larger than the sum of its proper divisors (669140065).
5304210449999 is an equidigital number, since it uses as much as digits as its factorization.
5304210449999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 669140064.
The product of its (nonzero) digits is 12597120, while the sum is 59.
The spelling of 5304210449999 in words is "five trillion, three hundred four billion, two hundred ten million, four hundred forty-nine thousand, nine hundred ninety-nine".
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