Search a number
-
+
5304210449981 is a prime number
BaseRepresentation
bin100110100101111101110…
…0101000110011000111101
3200210002002112202011201012
41031023323211012120331
51143401010333344411
615140415354125005
71055134164631052
oct115137345063075
920702075664635
105304210449981
111765559578193
12717ba9420765
132c62532ba1a1
14144a21b81029
1592e9487618b
hex4d2fb94663d

5304210449981 has 2 divisors, whose sum is σ = 5304210449982. Its totient is φ = 5304210449980.

The previous prime is 5304210449971. The next prime is 5304210450001. The reversal of 5304210449981 is 1899440124035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5141256944356 + 162953505625 = 2267434^2 + 403675^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5304210449981 is a prime.

It is a super-2 number, since 2×53042104499812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5304210449911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652105224990 + 2652105224991.

It is an arithmetic number, because the mean of its divisors is an integer number (2652105224991).

Almost surely, 25304210449981 is an apocalyptic number.

It is an amenable number.

5304210449981 is a deficient number, since it is larger than the sum of its proper divisors (1).

5304210449981 is an equidigital number, since it uses as much as digits as its factorization.

5304210449981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1244160, while the sum is 50.

The spelling of 5304210449981 in words is "five trillion, three hundred four billion, two hundred ten million, four hundred forty-nine thousand, nine hundred eighty-one".