Base | Representation |
---|---|
bin | 110001011001100100… |
… | …100101101101111011 |
3 | 12001220121120122122222 |
4 | 301121210211231323 |
5 | 1332112321341301 |
6 | 40211202034255 |
7 | 3555303501236 |
oct | 613144455573 |
9 | 161817518588 |
10 | 53042371451 |
11 | 2054a043823 |
12 | a34394898b |
13 | 500416b314 |
14 | 27d280641d |
15 | 15a6a0831b |
hex | c59925b7b |
53042371451 has 2 divisors, whose sum is σ = 53042371452. Its totient is φ = 53042371450.
The previous prime is 53042371427. The next prime is 53042371477. The reversal of 53042371451 is 15417324035.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53042371451 is a prime.
It is not a weakly prime, because it can be changed into another prime (53042371411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26521185725 + 26521185726.
It is an arithmetic number, because the mean of its divisors is an integer number (26521185726).
Almost surely, 253042371451 is an apocalyptic number.
53042371451 is a deficient number, since it is larger than the sum of its proper divisors (1).
53042371451 is an equidigital number, since it uses as much as digits as its factorization.
53042371451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 35.
Adding to 53042371451 its reverse (15417324035), we get a palindrome (68459695486).
The spelling of 53042371451 in words is "fifty-three billion, forty-two million, three hundred seventy-one thousand, four hundred fifty-one".
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