Base | Representation |
---|---|
bin | 100110100110000100000… |
… | …1101010010010101010011 |
3 | 200210002122022101211201220 |
4 | 1031030020031102111103 |
5 | 1143401424102430001 |
6 | 15140452403100123 |
7 | 1055142346466310 |
oct | 115141015222523 |
9 | 20702568354656 |
10 | 5304422311251 |
11 | 1765658121748 |
12 | 718048371643 |
13 | 2c628816829b |
14 | 144a41d6dd07 |
15 | 92ea8274c36 |
hex | 4d308352553 |
5304422311251 has 32 divisors (see below), whose sum is σ = 8150840721408. Its totient is φ = 3005656657920.
The previous prime is 5304422311241. The next prime is 5304422311261. The reversal of 5304422311251 is 1521132244035.
It is an interprime number because it is at equal distance from previous prime (5304422311241) and next prime (5304422311261).
It is not a de Polignac number, because 5304422311251 - 210 = 5304422310227 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5304422311211) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4582131 + ... + 5621811.
It is an arithmetic number, because the mean of its divisors is an integer number (254713772544).
Almost surely, 25304422311251 is an apocalyptic number.
5304422311251 is a deficient number, since it is larger than the sum of its proper divisors (2846418410157).
5304422311251 is a wasteful number, since it uses less digits than its factorization.
5304422311251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1041731.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 5304422311251 its reverse (1521132244035), we get a palindrome (6825554555286).
The spelling of 5304422311251 in words is "five trillion, three hundred four billion, four hundred twenty-two million, three hundred eleven thousand, two hundred fifty-one".
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