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5304422311241 is a prime number
BaseRepresentation
bin100110100110000100000…
…1101010010010101001001
3200210002122022101211201112
41031030020031102111021
51143401424102424431
615140452403100105
71055142346466264
oct115141015222511
920702568354645
105304422311241
111765658121739
12718048371635
132c6288168291
14144a41d6dcdb
1592ea8274c2b
hex4d308352549

5304422311241 has 2 divisors, whose sum is σ = 5304422311242. Its totient is φ = 5304422311240.

The previous prime is 5304422311211. The next prime is 5304422311261. The reversal of 5304422311241 is 1421132244035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2705297958841 + 2599124352400 = 1644779^2 + 1612180^2 .

It is a cyclic number.

It is not a de Polignac number, because 5304422311241 - 242 = 906375800137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5304422311198 and 5304422311207.

It is not a weakly prime, because it can be changed into another prime (5304422311211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652211155620 + 2652211155621.

It is an arithmetic number, because the mean of its divisors is an integer number (2652211155621).

Almost surely, 25304422311241 is an apocalyptic number.

It is an amenable number.

5304422311241 is a deficient number, since it is larger than the sum of its proper divisors (1).

5304422311241 is an equidigital number, since it uses as much as digits as its factorization.

5304422311241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 5304422311241 its reverse (1421132244035), we get a palindrome (6725554555276).

The spelling of 5304422311241 in words is "five trillion, three hundred four billion, four hundred twenty-two million, three hundred eleven thousand, two hundred forty-one".