Base | Representation |
---|---|
bin | 1100101001011… |
… | …0010001010011 |
3 | 10200210221002222 |
4 | 3022112101103 |
5 | 102034404212 |
6 | 5132531255 |
7 | 1212604061 |
oct | 312262123 |
9 | 120727088 |
10 | 53044307 |
11 | 27a3aa78 |
12 | 15920b2b |
13 | acb2c84 |
14 | 708b031 |
15 | 49cbc72 |
hex | 3296453 |
53044307 has 2 divisors, whose sum is σ = 53044308. Its totient is φ = 53044306.
The previous prime is 53044259. The next prime is 53044339. The reversal of 53044307 is 70344035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53044307 - 222 = 48850003 is a prime.
It is a super-2 number, since 2×530443072 = 5627397010220498, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (53044357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26522153 + 26522154.
It is an arithmetic number, because the mean of its divisors is an integer number (26522154).
Almost surely, 253044307 is an apocalyptic number.
53044307 is a deficient number, since it is larger than the sum of its proper divisors (1).
53044307 is an equidigital number, since it uses as much as digits as its factorization.
53044307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 26.
The square root of 53044307 is about 7283.1522708234. The cubic root of 53044307 is about 375.7332190681.
The spelling of 53044307 in words is "fifty-three million, forty-four thousand, three hundred seven".
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