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5304504130307 is a prime number
BaseRepresentation
bin100110100110000110100…
…0101011001101100000011
3200210002212000100200101022
41031030031011121230003
51143402111024132212
615140504444500055
71055144362106654
oct115141505315403
920702760320338
105304504130307
11176569a3255a8
1271806b84a62b
132c629c0b4625
14144a4cb8b52b
1592eb0537772
hex4d30d159b03

5304504130307 has 2 divisors, whose sum is σ = 5304504130308. Its totient is φ = 5304504130306.

The previous prime is 5304504130201. The next prime is 5304504130313. The reversal of 5304504130307 is 7030314054035.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5304504130307 is a prime.

It is a super-3 number, since 3×53045041303073 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (5304504130397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652252065153 + 2652252065154.

It is an arithmetic number, because the mean of its divisors is an integer number (2652252065154).

Almost surely, 25304504130307 is an apocalyptic number.

5304504130307 is a deficient number, since it is larger than the sum of its proper divisors (1).

5304504130307 is an equidigital number, since it uses as much as digits as its factorization.

5304504130307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75600, while the sum is 35.

The spelling of 5304504130307 in words is "five trillion, three hundred four billion, five hundred four million, one hundred thirty thousand, three hundred seven".