Base | Representation |
---|---|
bin | 100110100110010111001… |
… | …1010010000000101111001 |
3 | 200210011021222102121101112 |
4 | 1031030232122100011321 |
5 | 1143404232142303103 |
6 | 15141040140330105 |
7 | 1055164261360331 |
oct | 115145632200571 |
9 | 20704258377345 |
10 | 5305063244153 |
11 | 1765956998062 |
12 | 7181a6b43935 |
13 | 2c635ab9621a |
14 | 144aa31300c1 |
15 | 92ee467acd8 |
hex | 4d32e690179 |
5305063244153 has 2 divisors, whose sum is σ = 5305063244154. Its totient is φ = 5305063244152.
The previous prime is 5305063244119. The next prime is 5305063244161. The reversal of 5305063244153 is 3514423605035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5140594874944 + 164468369209 = 2267288^2 + 405547^2 .
It is a cyclic number.
It is not a de Polignac number, because 5305063244153 - 28 = 5305063243897 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5305063244153.
It is not a weakly prime, because it can be changed into another prime (5305063244113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652531622076 + 2652531622077.
It is an arithmetic number, because the mean of its divisors is an integer number (2652531622077).
Almost surely, 25305063244153 is an apocalyptic number.
It is an amenable number.
5305063244153 is a deficient number, since it is larger than the sum of its proper divisors (1).
5305063244153 is an equidigital number, since it uses as much as digits as its factorization.
5305063244153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 41.
Adding to 5305063244153 its reverse (3514423605035), we get a palindrome (8819486849188).
The spelling of 5305063244153 in words is "five trillion, three hundred five billion, sixty-three million, two hundred forty-four thousand, one hundred fifty-three".
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