Base | Representation |
---|---|
bin | 11000000111111111011110… |
… | …10001000111010101010011 |
3 | 20221211122022020011202002100 |
4 | 30003333233101013111103 |
5 | 23423142231230022003 |
6 | 304455210404451443 |
7 | 14113551040603320 |
oct | 1403775721072523 |
9 | 227748266152070 |
10 | 53051155314003 |
11 | 159a3961152380 |
12 | 5b498046a9b83 |
13 | 237a91946c642 |
14 | d1599244bb47 |
15 | 61eeb03a8ba3 |
hex | 303fef447553 |
53051155314003 has 48 divisors (see below), whose sum is σ = 95631769209600. Its totient is φ = 27531996171840.
The previous prime is 53051155313999. The next prime is 53051155314041. The reversal of 53051155314003 is 30041355115035.
53051155314003 is a `hidden beast` number, since 5 + 3 + 0 + 5 + 115 + 531 + 4 + 0 + 0 + 3 = 666.
It is not a de Polignac number, because 53051155314003 - 22 = 53051155313999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53051155314503) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 36856588 + ... + 38268921.
It is an arithmetic number, because the mean of its divisors is an integer number (1992328525200).
Almost surely, 253051155314003 is an apocalyptic number.
53051155314003 is a deficient number, since it is larger than the sum of its proper divisors (42580613895597).
53051155314003 is a wasteful number, since it uses less digits than its factorization.
53051155314003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75126552 (or 75126549 counting only the distinct ones).
The product of its (nonzero) digits is 67500, while the sum is 36.
The spelling of 53051155314003 in words is "fifty-three trillion, fifty-one billion, one hundred fifty-five million, three hundred fourteen thousand, three".
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