Base | Representation |
---|---|
bin | 11000000111111111011110… |
… | …10001000111011101000111 |
3 | 20221211122022020011202202212 |
4 | 30003333233101013131013 |
5 | 23423142231230031003 |
6 | 304455210404454035 |
7 | 14113551040604633 |
oct | 1403775721073507 |
9 | 227748266152685 |
10 | 53051155314503 |
11 | 159a3961152795 |
12 | 5b498046aa31b |
13 | 237a91946c938 |
14 | d1599244bdc3 |
15 | 61eeb03a8dd8 |
hex | 303fef447747 |
53051155314503 has 2 divisors, whose sum is σ = 53051155314504. Its totient is φ = 53051155314502.
The previous prime is 53051155314467. The next prime is 53051155314557. The reversal of 53051155314503 is 30541355115035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53051155314503 - 240 = 51951643686727 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53051151314503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26525577657251 + 26525577657252.
It is an arithmetic number, because the mean of its divisors is an integer number (26525577657252).
Almost surely, 253051155314503 is an apocalyptic number.
53051155314503 is a deficient number, since it is larger than the sum of its proper divisors (1).
53051155314503 is an equidigital number, since it uses as much as digits as its factorization.
53051155314503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 337500, while the sum is 41.
The spelling of 53051155314503 in words is "fifty-three trillion, fifty-one billion, one hundred fifty-five million, three hundred fourteen thousand, five hundred three".
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