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530512033111 = 1731206590183
BaseRepresentation
bin1111011100001001111…
…10110011010101010111
31212201100021222120222221
413232010332303111113
532142442040024421
61043414110003211
753220403610164
oct7560476632527
91781307876887
10530512033111
11194a97237595
12869974a6507
133b04761c038
141b96967706b
15dbee6a0841
hex7b84fb3557

530512033111 has 4 divisors (see below), whose sum is σ = 561718623312. Its totient is φ = 499305442912.

The previous prime is 530512033099. The next prime is 530512033127. The reversal of 530512033111 is 111330215035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 530512033111 - 27 = 530512032983 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530512033211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15603295075 + ... + 15603295108.

It is an arithmetic number, because the mean of its divisors is an integer number (140429655828).

Almost surely, 2530512033111 is an apocalyptic number.

530512033111 is a deficient number, since it is larger than the sum of its proper divisors (31206590201).

530512033111 is a wasteful number, since it uses less digits than its factorization.

530512033111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31206590200.

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 530512033111 its reverse (111330215035), we get a palindrome (641842248146).

The spelling of 530512033111 in words is "five hundred thirty billion, five hundred twelve million, thirty-three thousand, one hundred eleven".

Divisors: 1 17 31206590183 530512033111