Base | Representation |
---|---|
bin | 110001011010001000… |
… | …101110000110110001 |
3 | 12001221021101212011211 |
4 | 301122020232012301 |
5 | 1332122232433433 |
6 | 40212141040121 |
7 | 3555450140122 |
oct | 613210560661 |
9 | 161837355154 |
10 | 53051842993 |
11 | 20554422946 |
12 | a346b56041 |
13 | 5006106496 |
14 | 27d3b90049 |
15 | 15a77798cd |
hex | c5a22e1b1 |
53051842993 has 2 divisors, whose sum is σ = 53051842994. Its totient is φ = 53051842992.
The previous prime is 53051842981. The next prime is 53051843021. The reversal of 53051842993 is 39924815035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43683926049 + 9367916944 = 209007^2 + 96788^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53051842993 is a prime.
It is not a weakly prime, because it can be changed into another prime (53051849993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26525921496 + 26525921497.
It is an arithmetic number, because the mean of its divisors is an integer number (26525921497).
Almost surely, 253051842993 is an apocalyptic number.
It is an amenable number.
53051842993 is a deficient number, since it is larger than the sum of its proper divisors (1).
53051842993 is an equidigital number, since it uses as much as digits as its factorization.
53051842993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1166400, while the sum is 49.
The spelling of 53051842993 in words is "fifty-three billion, fifty-one million, eight hundred forty-two thousand, nine hundred ninety-three".
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