Base | Representation |
---|---|
bin | 11000001000000001000111… |
… | …00110000100000110010111 |
3 | 20221211201120102010001002212 |
4 | 30010000203212010012113 |
5 | 23423201031001033030 |
6 | 304455433445224035 |
7 | 14113611560645063 |
oct | 1404004346040627 |
9 | 227751512101085 |
10 | 53052033221015 |
11 | 159a4271764964 |
12 | 5b49a0a70201b |
13 | 237aa292cc04a |
14 | d15a36c96aa3 |
15 | 6200124be595 |
hex | 304023984197 |
53052033221015 has 16 divisors (see below), whose sum is σ = 64656870192000. Its totient is φ = 41783714499072.
The previous prime is 53052033221003. The next prime is 53052033221039. The reversal of 53052033221015 is 51012233025035.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53052033221015 is a prime.
It is a super-3 number, since 3×530520332210153 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 315007775 + ... + 315176144.
It is an arithmetic number, because the mean of its divisors is an integer number (4041054387000).
Almost surely, 253052033221015 is an apocalyptic number.
53052033221015 is a deficient number, since it is larger than the sum of its proper divisors (11604836970985).
53052033221015 is a wasteful number, since it uses less digits than its factorization.
53052033221015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 630184186.
The product of its (nonzero) digits is 27000, while the sum is 32.
The spelling of 53052033221015 in words is "fifty-three trillion, fifty-two billion, thirty-three million, two hundred twenty-one thousand, fifteen".
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