Base | Representation |
---|---|
bin | 11000001000000011011110… |
… | …00110011111110010101111 |
3 | 20221211211211200210210202000 |
4 | 30010001233012133302233 |
5 | 23423211124300424010 |
6 | 304500203301103343 |
7 | 14113655142342612 |
oct | 1404015706376257 |
9 | 227754750723660 |
10 | 53053300014255 |
11 | 159a4861841422 |
12 | 5b4a1029b7b53 |
13 | 237ab9b8ab548 |
14 | d15b17212179 |
15 | 6200888007c0 |
hex | 30406f19fcaf |
53053300014255 has 32 divisors (see below), whose sum is σ = 94321167083520. Its totient is φ = 28293836556960.
The previous prime is 53053300014157. The next prime is 53053300014259. The reversal of 53053300014255 is 55241000335035.
53053300014255 is a `hidden beast` number, since 5 + 30 + 533 + 0 + 0 + 0 + 1 + 42 + 55 = 666.
It is not a de Polignac number, because 53053300014255 - 28 = 53053300013999 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53053300014259) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5673091 + ... + 11759700.
It is an arithmetic number, because the mean of its divisors is an integer number (2947536471360).
Almost surely, 253053300014255 is an apocalyptic number.
53053300014255 is a deficient number, since it is larger than the sum of its proper divisors (41267867069265).
53053300014255 is a wasteful number, since it uses less digits than its factorization.
53053300014255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17455348 (or 17455342 counting only the distinct ones).
The product of its (nonzero) digits is 135000, while the sum is 36.
The spelling of 53053300014255 in words is "fifty-three trillion, fifty-three billion, three hundred million, fourteen thousand, two hundred fifty-five".
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