Base | Representation |
---|---|
bin | 100110100110100100010… |
… | …1101101101101111110011 |
3 | 200210012102201211110122121 |
4 | 1031031020231231233303 |
5 | 1143411133131211341 |
6 | 15141152023215111 |
7 | 1055211230424016 |
oct | 115151055555763 |
9 | 20705381743577 |
10 | 5305504553971 |
11 | 1766063008716 |
12 | 7182aa8a7497 |
13 | 2c63cb43c5ab |
14 | 144b059a937d |
15 | 9301d29e4d1 |
hex | 4d348b6dbf3 |
5305504553971 has 2 divisors, whose sum is σ = 5305504553972. Its totient is φ = 5305504553970.
The previous prime is 5305504553939. The next prime is 5305504554011. The reversal of 5305504553971 is 1793554055035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5305504553971 - 25 = 5305504553939 is a prime.
It is not a weakly prime, because it can be changed into another prime (5305504553471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652752276985 + 2652752276986.
It is an arithmetic number, because the mean of its divisors is an integer number (2652752276986).
Almost surely, 25305504553971 is an apocalyptic number.
5305504553971 is a deficient number, since it is larger than the sum of its proper divisors (1).
5305504553971 is an equidigital number, since it uses as much as digits as its factorization.
5305504553971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7087500, while the sum is 52.
The spelling of 5305504553971 in words is "five trillion, three hundred five billion, five hundred four million, five hundred fifty-three thousand, nine hundred seventy-one".
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