Base | Representation |
---|---|
bin | 100110100110100100011… |
… | …0000100100011111100011 |
3 | 200210012102210020111102212 |
4 | 1031031020300210133203 |
5 | 1143411133324134444 |
6 | 15141152051232335 |
7 | 1055211236662223 |
oct | 115151060443743 |
9 | 20705383214385 |
10 | 5305505302499 |
11 | 176606347a036 |
12 | 7182aaba86ab |
13 | 2c63cb6421cc |
14 | 144b05b22083 |
15 | 9301d39b19e |
hex | 4d348c247e3 |
5305505302499 has 2 divisors, whose sum is σ = 5305505302500. Its totient is φ = 5305505302498.
The previous prime is 5305505302483. The next prime is 5305505302529. The reversal of 5305505302499 is 9942035055035.
5305505302499 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5305505302499 - 24 = 5305505302483 is a prime.
It is not a weakly prime, because it can be changed into another prime (5305505302099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652752651249 + 2652752651250.
It is an arithmetic number, because the mean of its divisors is an integer number (2652752651250).
Almost surely, 25305505302499 is an apocalyptic number.
5305505302499 is a deficient number, since it is larger than the sum of its proper divisors (1).
5305505302499 is an equidigital number, since it uses as much as digits as its factorization.
5305505302499 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3645000, while the sum is 50.
The spelling of 5305505302499 in words is "five trillion, three hundred five billion, five hundred five million, three hundred two thousand, four hundred ninety-nine".
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