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530551113313115 = 5106110222662623
BaseRepresentation
bin111100010100010001000111…
…0101001001110101101011011
32120120112012011022012110021002
41320220202032221032231123
51024020022140002004430
65120215452223535215
7216516024115411166
oct17050421651165533
92516465138173232
10530551113313115
11144060511031a54
124b60843a45a50b
1319a069a8552c7b
149502b4d162add
154150cba7b5845
hex1e2888ea4eb5b

530551113313115 has 4 divisors (see below), whose sum is σ = 636661335975744. Its totient is φ = 424440890650488.

The previous prime is 530551113313103. The next prime is 530551113313201. The reversal of 530551113313115 is 511313311155035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 530551113313115 - 28 = 530551113312859 is a prime.

It is a super-3 number, since 3×5305511133131153 (a number of 45 digits) contains 333 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53055111331307 + ... + 53055111331316.

It is an arithmetic number, because the mean of its divisors is an integer number (159165333993936).

Almost surely, 2530551113313115 is an apocalyptic number.

530551113313115 is a deficient number, since it is larger than the sum of its proper divisors (106110222662629).

530551113313115 is a wasteful number, since it uses less digits than its factorization.

530551113313115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 106110222662628.

The product of its (nonzero) digits is 50625, while the sum is 38.

The spelling of 530551113313115 in words is "five hundred thirty trillion, five hundred fifty-one billion, one hundred thirteen million, three hundred thirteen thousand, one hundred fifteen".

Divisors: 1 5 106110222662623 530551113313115