Base | Representation |
---|---|
bin | 111100010100010001000111… |
… | …0101001001110101101001111 |
3 | 2120120112012011022012110020122 |
4 | 1320220202032221032231033 |
5 | 1024020022140002004403 |
6 | 5120215452223535155 |
7 | 216516024115411151 |
oct | 17050421651165517 |
9 | 2516465138173218 |
10 | 530551113313103 |
11 | 144060511031a43 |
12 | 4b60843a45a4bb |
13 | 19a069a8552c6c |
14 | 9502b4d162ad1 |
15 | 4150cba7b5838 |
hex | 1e2888ea4eb4f |
530551113313103 has 2 divisors, whose sum is σ = 530551113313104. Its totient is φ = 530551113313102.
The previous prime is 530551113313061. The next prime is 530551113313201. The reversal of 530551113313103 is 301313311155035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530551113313103 - 210 = 530551113312079 is a prime.
It is a super-2 number, since 2×5305511133131032 (a number of 30 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530551113313703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265275556656551 + 265275556656552.
It is an arithmetic number, because the mean of its divisors is an integer number (265275556656552).
Almost surely, 2530551113313103 is an apocalyptic number.
530551113313103 is a deficient number, since it is larger than the sum of its proper divisors (1).
530551113313103 is an equidigital number, since it uses as much as digits as its factorization.
530551113313103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30375, while the sum is 35.
Adding to 530551113313103 its reverse (301313311155035), we get a palindrome (831864424468138).
The spelling of 530551113313103 in words is "five hundred thirty trillion, five hundred fifty-one billion, one hundred thirteen million, three hundred thirteen thousand, one hundred three".
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