Base | Representation |
---|---|
bin | 111100010100010001000111… |
… | …0101001001111101100001011 |
3 | 2120120112012011022012122202211 |
4 | 1320220202032221033230023 |
5 | 1024020022140002122011 |
6 | 5120215452224005551 |
7 | 216516024115425664 |
oct | 17050421651175413 |
9 | 2516465138178684 |
10 | 530551113317131 |
11 | 144060511034a75 |
12 | 4b60843a4608b7 |
13 | 19a069a8554a4a |
14 | 9502b4d16436b |
15 | 4150cba7b6b21 |
hex | 1e2888ea4fb0b |
530551113317131 has 2 divisors, whose sum is σ = 530551113317132. Its totient is φ = 530551113317130.
The previous prime is 530551113317087. The next prime is 530551113317297. The reversal of 530551113317131 is 131713311155035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530551113317131 - 219 = 530551112792843 is a prime.
It is a super-2 number, since 2×5305511133171312 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (530551113317431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265275556658565 + 265275556658566.
It is an arithmetic number, because the mean of its divisors is an integer number (265275556658566).
Almost surely, 2530551113317131 is an apocalyptic number.
530551113317131 is a deficient number, since it is larger than the sum of its proper divisors (1).
530551113317131 is an equidigital number, since it uses as much as digits as its factorization.
530551113317131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 70875, while the sum is 40.
The spelling of 530551113317131 in words is "five hundred thirty trillion, five hundred fifty-one billion, one hundred thirteen million, three hundred seventeen thousand, one hundred thirty-one".
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