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530551113317131 is a prime number
BaseRepresentation
bin111100010100010001000111…
…0101001001111101100001011
32120120112012011022012122202211
41320220202032221033230023
51024020022140002122011
65120215452224005551
7216516024115425664
oct17050421651175413
92516465138178684
10530551113317131
11144060511034a75
124b60843a4608b7
1319a069a8554a4a
149502b4d16436b
154150cba7b6b21
hex1e2888ea4fb0b

530551113317131 has 2 divisors, whose sum is σ = 530551113317132. Its totient is φ = 530551113317130.

The previous prime is 530551113317087. The next prime is 530551113317297. The reversal of 530551113317131 is 131713311155035.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 530551113317131 - 219 = 530551112792843 is a prime.

It is a super-2 number, since 2×5305511133171312 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (530551113317431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265275556658565 + 265275556658566.

It is an arithmetic number, because the mean of its divisors is an integer number (265275556658566).

Almost surely, 2530551113317131 is an apocalyptic number.

530551113317131 is a deficient number, since it is larger than the sum of its proper divisors (1).

530551113317131 is an equidigital number, since it uses as much as digits as its factorization.

530551113317131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 70875, while the sum is 40.

The spelling of 530551113317131 in words is "five hundred thirty trillion, five hundred fifty-one billion, one hundred thirteen million, three hundred seventeen thousand, one hundred thirty-one".