Base | Representation |
---|---|
bin | 110001011010010101… |
… | …111011011010110001 |
3 | 12001221111220202200212 |
4 | 301122111323122301 |
5 | 1332124124233033 |
6 | 40212343153505 |
7 | 3555521440436 |
oct | 613225733261 |
9 | 161844822625 |
10 | 53055305393 |
11 | 20556378232 |
12 | a348145895 |
13 | 5006a4943c |
14 | 27d4411b8d |
15 | 15a7c10748 |
hex | c5a57b6b1 |
53055305393 has 2 divisors, whose sum is σ = 53055305394. Its totient is φ = 53055305392.
The previous prime is 53055305371. The next prime is 53055305431. The reversal of 53055305393 is 39350355035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43200375409 + 9854929984 = 207847^2 + 99272^2 .
It is a cyclic number.
It is not a de Polignac number, because 53055305393 - 214 = 53055289009 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53055305393.
It is not a weakly prime, because it can be changed into another prime (53051305393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26527652696 + 26527652697.
It is an arithmetic number, because the mean of its divisors is an integer number (26527652697).
Almost surely, 253055305393 is an apocalyptic number.
It is an amenable number.
53055305393 is a deficient number, since it is larger than the sum of its proper divisors (1).
53055305393 is an equidigital number, since it uses as much as digits as its factorization.
53055305393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 455625, while the sum is 41.
The spelling of 53055305393 in words is "fifty-three billion, fifty-five million, three hundred five thousand, three hundred ninety-three".
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