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53055947700 = 223452717192897
BaseRepresentation
bin110001011010011000…
…011000001110110100
312001221120010101210000
4301122120120032310
51332124310311300
640212405031300
73555530054160
oct613230301664
9161846111700
1053055947700
1120556776868
12a3483b5530
135006c128c2
1427d453bca0
1515a7cdac00
hexc5a6183b4

53055947700 has 720 divisors, whose sum is σ = 219147223680. Its totient is φ = 10809262080.

The previous prime is 53055947687. The next prime is 53055947741. The reversal of 53055947700 is 774955035.

53055947700 is a `hidden beast` number, since 53 + 0 + 5 + 594 + 7 + 7 + 0 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 18312652 + ... + 18315548.

It is an arithmetic number, because the mean of its divisors is an integer number (304371144).

Almost surely, 253055947700 is an apocalyptic number.

53055947700 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53055947700, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (109573611840).

53055947700 is an abundant number, since it is smaller than the sum of its proper divisors (166091275980).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53055947700 is a wasteful number, since it uses less digits than its factorization.

53055947700 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2966 (or 2950 counting only the distinct ones).

The product of its (nonzero) digits is 661500, while the sum is 45.

The spelling of 53055947700 in words is "fifty-three billion, fifty-five million, nine hundred forty-seven thousand, seven hundred".