Base | Representation |
---|---|
bin | 110001011010011000… |
… | …101011001000001111 |
3 | 12001221120021022221210 |
4 | 301122120223020033 |
5 | 1332124320300403 |
6 | 40212410425503 |
7 | 3555530525634 |
oct | 613230531017 |
9 | 161846238853 |
10 | 53056025103 |
11 | 20556819a34 |
12 | a348432293 |
13 | 5006c3bbc3 |
14 | 27d455c18b |
15 | 15a7d03b03 |
hex | c5a62b20f |
53056025103 has 8 divisors (see below), whose sum is σ = 73180724400. Its totient is φ = 34151004608.
The previous prime is 53056025093. The next prime is 53056025119. The reversal of 53056025103 is 30152065035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53056025103 - 26 = 53056025039 is a prime.
It is a super-3 number, since 3×530560251033 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53056025003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 304919598 + ... + 304919771.
It is an arithmetic number, because the mean of its divisors is an integer number (9147590550).
Almost surely, 253056025103 is an apocalyptic number.
53056025103 is a deficient number, since it is larger than the sum of its proper divisors (20124699297).
53056025103 is a wasteful number, since it uses less digits than its factorization.
53056025103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 609839401.
The product of its (nonzero) digits is 13500, while the sum is 30.
The spelling of 53056025103 in words is "fifty-three billion, fifty-six million, twenty-five thousand, one hundred three".
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