Base | Representation |
---|---|
bin | 100110100110110100101… |
… | …0100010100110011101011 |
3 | 200210020211212002120010111 |
4 | 1031031221110110303223 |
5 | 1143413243143440342 |
6 | 15141322203155151 |
7 | 1055230621660666 |
oct | 115155124246353 |
9 | 20706755076114 |
10 | 5306051546347 |
11 | 1766313851132 |
12 | 718421b15ab7 |
13 | 2c6487868b16 |
14 | 144b584b46dd |
15 | 930512eb217 |
hex | 4d369514ceb |
5306051546347 has 2 divisors, whose sum is σ = 5306051546348. Its totient is φ = 5306051546346.
The previous prime is 5306051546339. The next prime is 5306051546399. The reversal of 5306051546347 is 7436451506035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5306051546347 - 23 = 5306051546339 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5306051546347.
It is not a weakly prime, because it can be changed into another prime (5306051544347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2653025773173 + 2653025773174.
It is an arithmetic number, because the mean of its divisors is an integer number (2653025773174).
Almost surely, 25306051546347 is an apocalyptic number.
5306051546347 is a deficient number, since it is larger than the sum of its proper divisors (1).
5306051546347 is an equidigital number, since it uses as much as digits as its factorization.
5306051546347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536000, while the sum is 49.
The spelling of 5306051546347 in words is "five trillion, three hundred six billion, fifty-one million, five hundred forty-six thousand, three hundred forty-seven".
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