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53062803887 = 531001184979
BaseRepresentation
bin110001011010110010…
…100010000110101111
312001222001000201200212
4301122302202012233
51332133034211022
640213212013035
73555642251102
oct613262420657
9161861021625
1053062803887
112055a629a35
12a34a76117b
135008473512
1427d5404739
1515a86e23e2
hexc5aca21af

53062803887 has 4 divisors (see below), whose sum is σ = 54063988920. Its totient is φ = 52061618856.

The previous prime is 53062803883. The next prime is 53062803901. The reversal of 53062803887 is 78830826035.

53062803887 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53062803887 - 22 = 53062803883 is a prime.

It is a super-2 number, since 2×530628038872 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53062803883) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500592437 + ... + 500592542.

It is an arithmetic number, because the mean of its divisors is an integer number (13515997230).

Almost surely, 253062803887 is an apocalyptic number.

53062803887 is a deficient number, since it is larger than the sum of its proper divisors (1001185033).

53062803887 is a wasteful number, since it uses less digits than its factorization.

53062803887 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1001185032.

The product of its (nonzero) digits is 1935360, while the sum is 50.

The spelling of 53062803887 in words is "fifty-three billion, sixty-two million, eight hundred three thousand, eight hundred eighty-seven".

Divisors: 1 53 1001184979 53062803887