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530640215343317 = 2323071313710579
BaseRepresentation
bin111100010100111010100110…
…1100010100000000011010101
32120120211201010222101120101202
41320221311031202200003111
51024023002130111441232
65120324425525402245
7216525330132233042
oct17051651542400325
92516751128346352
10530640215343317
11144095284888042
124b621766569385
1319a1220830c971
1495071a2ab21c9
154153282db7162
hex1e29d4d8a00d5

530640215343317 has 4 divisors (see below), whose sum is σ = 553711529053920. Its totient is φ = 507568901632716.

The previous prime is 530640215343281. The next prime is 530640215343341. The reversal of 530640215343317 is 713343512046035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530640215343317 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530640215343377) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11535656855267 + ... + 11535656855312.

It is an arithmetic number, because the mean of its divisors is an integer number (138427882263480).

Almost surely, 2530640215343317 is an apocalyptic number.

It is an amenable number.

530640215343317 is a deficient number, since it is larger than the sum of its proper divisors (23071313710603).

530640215343317 is a wasteful number, since it uses less digits than its factorization.

530640215343317 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23071313710602.

The product of its (nonzero) digits is 2721600, while the sum is 47.

The spelling of 530640215343317 in words is "five hundred thirty trillion, six hundred forty billion, two hundred fifteen million, three hundred forty-three thousand, three hundred seventeen".

Divisors: 1 23 23071313710579 530640215343317