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5306477 = 11482407
BaseRepresentation
bin10100001111100001101101
3100222121010012
4110033201231
52324301402
6305423005
763050531
oct24174155
910877105
105306477
112aa4920
12193aa65
13113a437
149c1bc1
156ec452
hex50f86d

5306477 has 4 divisors (see below), whose sum is σ = 5788896. Its totient is φ = 4824060.

The previous prime is 5306473. The next prime is 5306479. The reversal of 5306477 is 7746035.

5306477 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5306477 - 22 = 5306473 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5306471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241193 + ... + 241214.

It is an arithmetic number, because the mean of its divisors is an integer number (1447224).

Almost surely, 25306477 is an apocalyptic number.

It is an amenable number.

5306477 is a deficient number, since it is larger than the sum of its proper divisors (482419).

5306477 is a wasteful number, since it uses less digits than its factorization.

5306477 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 482418.

The product of its (nonzero) digits is 17640, while the sum is 32.

The square root of 5306477 is about 2303.5791716370. The cubic root of 5306477 is about 174.4223347129.

It can be divided in two parts, 530 and 6477, that added together give a palindrome (7007).

The spelling of 5306477 in words is "five million, three hundred six thousand, four hundred seventy-seven".

Divisors: 1 11 482407 5306477