Base | Representation |
---|---|
bin | 111100010101000101011010… |
… | …1101110111010100000101101 |
3 | 2120120220221002102102012011201 |
4 | 1320222022311232322200231 |
5 | 1024023342210143424430 |
6 | 5120343230145245501 |
7 | 216530111460633160 |
oct | 17052126556724055 |
9 | 2516827072365151 |
10 | 530663438264365 |
11 | 1440a411159537a |
12 | 4b626167933891 |
13 | 19a1446961cc73 |
14 | 950836702bad7 |
15 | 4153b91a5c8ca |
hex | 1e2a2b5bba82d |
530663438264365 has 16 divisors (see below), whose sum is σ = 737736412025088. Its totient is φ = 358898795035776.
The previous prime is 530663438264359. The next prime is 530663438264387. The reversal of 530663438264365 is 563462834366035.
It is a cyclic number.
It is not a de Polignac number, because 530663438264365 - 217 = 530663438133293 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 530663438264297 and 530663438264306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 103848028417 + ... + 103848033526.
It is an arithmetic number, because the mean of its divisors is an integer number (46108525751568).
Almost surely, 2530663438264365 is an apocalyptic number.
It is an amenable number.
530663438264365 is a deficient number, since it is larger than the sum of its proper divisors (207072973760723).
530663438264365 is a wasteful number, since it uses less digits than its factorization.
530663438264365 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 207696062028.
The product of its (nonzero) digits is 671846400, while the sum is 64.
The spelling of 530663438264365 in words is "five hundred thirty trillion, six hundred sixty-three billion, four hundred thirty-eight million, two hundred sixty-four thousand, three hundred sixty-five".
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