Base | Representation |
---|---|
bin | 111100010101110111101101… |
… | …1000011101000100000111111 |
3 | 2120121022020212011011110211120 |
4 | 1320223233123003220200333 |
5 | 1024032124401242310241 |
6 | 5120505011024122023 |
7 | 216540654021634464 |
oct | 17053573303504077 |
9 | 2517266764143746 |
10 | 530771438635071 |
11 | 1441359a2a21397 |
12 | 4b643088a66313 |
13 | 19a216bb77246a |
14 | 950d69081166b |
15 | 41568b3317666 |
hex | 1e2bbdb0e883f |
530771438635071 has 32 divisors (see below), whose sum is σ = 713215843307520. Its totient is φ = 351097823808000.
The previous prime is 530771438635043. The next prime is 530771438635073. The reversal of 530771438635071 is 170536834177035.
It is not a de Polignac number, because 530771438635071 - 219 = 530771438110783 is a prime.
It is a super-2 number, since 2×5307714386350712 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 530771438634996 and 530771438635014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530771438635073) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 388114536 + ... + 389479698.
It is an arithmetic number, because the mean of its divisors is an integer number (22287995103360).
Almost surely, 2530771438635071 is an apocalyptic number.
530771438635071 is a deficient number, since it is larger than the sum of its proper divisors (182444404672449).
530771438635071 is a wasteful number, since it uses less digits than its factorization.
530771438635071 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1367087.
The product of its (nonzero) digits is 44452800, while the sum is 60.
The spelling of 530771438635071 in words is "five hundred thirty trillion, seven hundred seventy-one billion, four hundred thirty-eight million, six hundred thirty-five thousand, seventy-one".
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