Base | Representation |
---|---|
bin | 1001111000110001… |
… | …00110011000100011 |
3 | 111200221000211020212 |
4 | 10330120212120203 |
5 | 41332330031211 |
6 | 2234413524335 |
7 | 245352446213 |
oct | 47430463043 |
9 | 14627024225 |
10 | 5308048931 |
11 | 22842897a9 |
12 | 10417a36ab |
13 | 667917173 |
14 | 384d6c243 |
15 | 21100538b |
hex | 13c626623 |
5308048931 has 2 divisors, whose sum is σ = 5308048932. Its totient is φ = 5308048930.
The previous prime is 5308048913. The next prime is 5308048961. The reversal of 5308048931 is 1398408035.
5308048931 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
Together with previous prime (5308048913) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5308048931 - 210 = 5308047907 is a prime.
It is a super-2 number, since 2×53080489312 = 56350766907780485522, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5308048961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2654024465 + 2654024466.
It is an arithmetic number, because the mean of its divisors is an integer number (2654024466).
Almost surely, 25308048931 is an apocalyptic number.
5308048931 is a deficient number, since it is larger than the sum of its proper divisors (1).
5308048931 is an equidigital number, since it uses as much as digits as its factorization.
5308048931 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 41.
The square root of 5308048931 is about 72856.3582057187. The cubic root of 5308048931 is about 1744.3955598202.
The spelling of 5308048931 in words is "five billion, three hundred eight million, forty-eight thousand, nine hundred thirty-one".
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