Base | Representation |
---|---|
bin | 100110101000101011010… |
… | …0001111011010111001111 |
3 | 200210122010012201121201210 |
4 | 1031101112201323113033 |
5 | 1143444421003443320 |
6 | 15143221131305503 |
7 | 1055431345302201 |
oct | 115212641732717 |
9 | 20718105647653 |
10 | 5310031312335 |
11 | 1767a76275232 |
12 | 7191528ab293 |
13 | 2c6970224739 |
14 | 145014c7c771 |
15 | 931d58c60e0 |
hex | 4d45687b5cf |
5310031312335 has 8 divisors (see below), whose sum is σ = 8496050099760. Its totient is φ = 2832016699904.
The previous prime is 5310031312307. The next prime is 5310031312379. The reversal of 5310031312335 is 5332131300135.
5310031312335 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5310031312335 - 210 = 5310031311311 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 177001043730 + ... + 177001043759.
It is an arithmetic number, because the mean of its divisors is an integer number (1062006262470).
Almost surely, 25310031312335 is an apocalyptic number.
5310031312335 is a deficient number, since it is larger than the sum of its proper divisors (3186018787425).
5310031312335 is a wasteful number, since it uses less digits than its factorization.
5310031312335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 354002087497.
The product of its (nonzero) digits is 12150, while the sum is 30.
The spelling of 5310031312335 in words is "five trillion, three hundred ten billion, thirty-one million, three hundred twelve thousand, three hundred thirty-five".
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